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Feliz [49]
2 years ago
12

Amy started picking blueberries at 1{:}37 \text { p.M.}1:37 p.M.1, colon, 37, start text, space, p, point, m, point, end text an

d finished picking at 2{:}21\text { p.M.}2:21 p.M.2, colon, 21, start text, space, p, point, m, point, end text
Mathematics
1 answer:
Umnica [9.8K]2 years ago
5 0

Complete question :

Amy started picking blueberries at 1{:}37 \text { p.M.}1:37 p.M.1, colon, 37, start text, space, p, point, m, point, end text and finished picking at 2{:}21\text { p.M.}2:21 p.M.2, colon, 21, start text, space, p, point, m, point, end text. The time spent picking blueberries

Answer:

44 minutes

Step-by-step explanation:

Given that :

Start time = 1:37 pm

End time = 2:21 pm

The time difference is obtained by subtracting the start time from the end time :

. End time - start time

2:21 pm - 1:37 pm

From 1:37 pm to 2 pm = 23 minutes

From 2 pm to 2:21 pm = 21 minutes

Total minutes = (23 + 21) minutes = 44 minutes

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What is AE ? Enter your answer in the box. units Two segments A D and B C intersect at point E to form two triangles A B E and D
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Answer:

The length of AE is 20 units.

Step-by-step explanation:

Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.

we have to find the length of AE

AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD  

In ΔABE and ΔDCE

∠EAB=∠EDC      (∵Alternate angles)

∠EBA=∠ECD      (∵Alternate angles)

By AA similarity, ΔABE ≈ ΔDCE

therefore, \frac{AE}{ED}=\frac{AB}{CD}

⇒ \frac{2x+10}{x+3}=\frac{10}{4}

⇒ 8x+40=10x+30

⇒ x=5

Hence, AE=2x+10=2(5)+10=20 units

The length of AE is 20 units.

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3 years ago
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