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amm1812
3 years ago
15

How many solutions does this equation have?

Mathematics
2 answers:
juin [17]3 years ago
6 0

Answer:

infinitely many solutions

Step-by-step explanation:

Bess [88]3 years ago
4 0

Answer: One solution (1 1/6)

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In the function y=1/2x^2 , what effect does the number 1/2 have on the graph, as compared to the graph of the function y=x^2 ?
Masja [62]

Answer:

D isn't the correct answer. It's "It shrinks the graph vertically to 1/2 its original height."

Step-by-step explanation:

I'm not sure why though this is right because I graphed it, and I don't see how that could be the right answer.

8 0
3 years ago
Read 2 more answers
The cost to a store for an MP3 player is $60. The selling price is $105. A classmate says that the markup is 175% because $105$6
blsea [12.9K]

It is given that the cost price of the MP3 player is $60 and the selling price is $105.

The markup is given by the formula:

Markup = \frac{S.P.}{C.P.} (100)

= \frac{105}{60} (100)

= 1.75 × 100

= 175%

Yes, the classmate is correct.

Hence, the markup is 175% and the classmate is correct.

5 0
3 years ago
Which choices are correct when determining the distance between −56 and 69?
Gnesinka [82]

The choices that are correct when determining the distance between −56 and 69 are |-56 - 69| and 125 units

<h3>How to determine the choices that are correct when determining the distance between −56 and 69?</h3>

The endpoints are given as

−56 and 69

The distance between the endpoints is calculated using

Distance = |Difference between  endpoints|

So, we have:

Distance = |-56 - 69|

Evaluate

Distance = 125

Hence, the choices that are correct when determining the distance between −56 and 69 are |-56 - 69| and 125 units

Read more about number line at

brainly.com/question/4727909

#SPJ1

6 0
2 years ago
Try it
joja [24]
Sorry if u rlly need the answer ask me

7 0
3 years ago
Find the area of a circle whose circumference is 8
Virty [35]
5.09
rule is A = C^2
____
4π
area is equal to C power 2 then everything divided by 4π
6 0
3 years ago
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