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jasenka [17]
3 years ago
6

Write 12x – 3y= –24 in slope-intercept form.

Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0

Answer: y=4x+8

Step-by-step explanation:

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Ms. Bradshaw bakes a whole chocolate cake. Logan ate 3/10 of the cake on Monday and 1/10 of the cake on Tuesday. What fraction o
natima [27]
1/10+3/10=4/10
10-4=6
6/10 was left
5 0
2 years ago
Solve for m:<br><br> 13=2m+5<br><br><br> Please explain how you figured this out.
Temka [501]

Answer:

m=\left(2m+5\right)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Elijah brought a total of 16 pounds of peanuts and cashew nuts and paid $49.50 if peanuts cost $2.75 per pound and cashews nuts
maria [59]

Answer:

The number of pounds of cashew is 11

Step-by-step explanation:

Let P represent the peanut

Let C represent the cashew nut.

From question, we were told that Elijah brought a total of 16 pounds of peanuts and cashew nuts. This can be written as:

P + C = 16 (1)

The total cost = $49.50

Cost per peanut = $2.75

Cost per cashew = $3.25

The above can be represented as:

49.50 = 2.75P + 3.25C. (2)

From equation 1,

P + C = 16

P = 16 — C

Substitute the value of P into equation 2:

49.50 = 2.75P + 3.25C.

49.50 = 2.75(16 — C) + 3.25C

49.50 = 44 — 2.75C + 3.25C

49.50 = 44 + 0.5C

Collect like terms

49.50 — 44 = 0.5C

5.5 = 0.5C

Divide both side by 0.5

C = 5.5/0.5

C = 11

Therefore, the number of pounds of cashew is 11

8 0
3 years ago
For a taxi driver, which measures must be accurate? Check all that apply.
astra-53 [7]

Answer:

Them all as he has to know how far he travels the customer rate to see is there is an increase of decrease price of gasoline to see if it's affecting g his outcome and price per miles for obvious reasons haha

3 0
3 years ago
Read 2 more answers
Find the standard deviation of 21, 31, 26, 24, 28, 26
Vesnalui [34]

Given the dataset

x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}

We start by computing the average:

\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26

We compute the difference bewteen each element and the average:

x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}

We square those differences:

(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}

And take the average of those squared differences: we sum them

\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69

And we divide by the number of elements:

\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5

Finally, we take the square root of this quantity and we have the standard deviation:

\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39

8 0
3 years ago
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