3 years ago

Write 12x – 3y= –24 in slope-intercept form.

Mathematics

1 answer:

a_sh-v [17]3 years ago

5 0

Answer: y=4x+8

Step-by-step explanation:

You might be interested in

Guys im not in high school im in middle school

ella [17]

Answer:

ok that is awesome

4 0

3 years ago

Read 2 more answers

X=2x+3-17 how do i solve this

nikitadnepr [17]

Answer:

x=-4.67

Step-by-step explanation:

add like terms 3-17

then take x=2x-14

add 2x to both sides

3x=-14

divide by 3 and you get your answer

5 0

3 years ago

Read 2 more answers

Which statement is true? A. In any right triangle, the sine of one acute angle is equal to the cosine of the other acute angle.

mr Goodwill [35]

That would be choice 2. One acute angle is the complement of the other

eg in a 90-60-30 triangle sine 30 = cos 60

8 0

3 years ago

Read 2 more answers

victus00 [196]

Answer:

With a vertex (h, k) at (0, 3) and given that a = -3, then the equation of this parabola in vertex form is as follows:

y = a(x - h)2 + k

y = -3(x - 0)2 + 3

y = -3x2 + 3

Step-by-step explanation:

7 0

3 years ago

Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1

Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in $\frac{1}{1.5}$ minutes

Hence

10.50 mph will be increased in $\frac{1}{1.5} \times 10.50$ minutes

$= \frac{10.5}{1.5}$

$=7$

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0

3 years ago