in a sale, Richard bought a TV for £300. The original price of the TV was £380. What was the percentage discount on the TV?
2 answers:
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Answer:
1. ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
1.25(25)+admission=43.75
31.25+admission=43.75
minus 31.25 from both sides
admission=12.50
a.
y=1.25x+12.5
b.
x is number of tickets and y is total cost
c. math, seriously, just read what is above option a (the one in the top of the answer)
if you're too lazy then:
ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
2.
(a)
m = (y2 - y1) / (x2 - x1) = (4 - 9)/(-2 - 8) = -5/(-10) = 1/2
(b)
y - y1 = m(x - x1)
Using the first given point,
y - 9 = (1/2)(x - 8)
Using the second given point,
y - 4 = (1/2)(x + 2)
note they both simplify to
y = (1/2)x + 5
(c)
y = (1/2)x + 5
3.
Answer:
b) 95 percent confidence interval for this single-sample t test
[11.64, 16.36]
Step-by-step explanation:
Explanation:-
Given data a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.
Sample size 'n' =62
sample mean x⁻ = 14
sample standard deviation 'S' = 9.3
<u>95 percent confidence interval for this single-sample t test</u>
The values are the <u>95 percent confidence interval for the population mean 'μ'</u>
Degrees of freedom γ=n-1=62-1=61
t₀.₀₅ = 1.9996 at 61 degrees of freedom
(14-2.361 , 14 + 2.361)
[(11.64 , 16.36]
<u>Conclusion:-</u>
95 percent confidence interval for this single-sample t test
[11.64, 16.36]
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