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Rom4ik [11]
3 years ago
14

What is the answer to 2+2

Mathematics
2 answers:
ollegr [7]3 years ago
6 0
It seems to be 4 probably, but if it’s right award me brainliest I’m desperate
Bingel [31]3 years ago
5 0

Answer:

4

Step-by-step explanation:

2 + 2 = 4

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Simplify the expression:<br> 9v–4v+7v
EleoNora [17]

Step-by-step explanation:

9v-4v+7v

= 5v+7v

= 12v

The answer is 12v

7 0
3 years ago
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s2008m [1.1K]

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2 years ago
1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav
OLga [1]

Answer:

(1) y=C, C\neq0

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant,  C \neq 0, has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

\Rightarrow x=C, where C\neq0.

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0
3 years ago
Find f(x)+g(x), given f(x)=x^2-8 and g(x)=-2-x^2
Gnoma [55]

\left(x^2-8\right)+\left(-2-x^2\right)=-10

\left(x^2-8\right)+\left(-2-x^2\right)

=x^2-8-2-x^2

=x^2-x^2-8-2

=-8-2

=-10

8 0
2 years ago
The difference of 7 and a number n​
Effectus [21]

Answer:

7 - n

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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