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3 years ago

I need help with this question!

Mathematics

1 answer:

ki77a [65]3 years ago

4 0

Answer:

Step-by-step explanation:

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Ben wants to try a new honey-glazed salmon recipe. He starts with 1

RSB [31]

1/4 i hope this helps u

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3 years ago

Leigh has a piece of rope thst is 6 2/3 feet long. how do you write 6 2/3 as a fraction greater than 1

crimeas [40]

20/3 - Take the 6 2/3, multiply the 6 and the 3 (6 x 3 = 18), then add the 2 (18 + 2 = 20). Put that number over the original 3 and you've got yourself a mixed number. i hope it help =)

3 0

3 years ago

The product of 6 and a number is the same as 40 less than twice that same number. find the number. the answers are 4,20,-20,-4

ycow [4]

Solving this involves basic arithmetic.

The number is -10

Let the number that is a product with 6 be x.

This product is the same as 40 less than twice that same number.

Thus; 6x = 2x - 40

Rearranging, we have;

6x -2x = -40

4x = -40

x = -40/4

x = -10

Read more at; brainly.com/question/24621972

7 0

3 years ago

Read 2 more answers

GIVING BRAINIEST IF THE ANSWERS CORRECT

Zolol [24]

Answer:

<h2>1st option </h2>

Step-by-step explanation:

${6}^{6} . {6}^{ - 9}$

$= {6}^{6 + ( - 9)}$

$= {6}^{ - 3}$

$= \frac{1}{ {6}^{3} } (ans)$

5 0

3 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers