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sesenic [268]
2 years ago
10

(-4) x 5 + (-6)

Mathematics
1 answer:
Svetllana [295]2 years ago
8 0

<h2>DOWNLOAD </h2><h2>THE</h2><h2>APP </h2><h2>PHOTOMATH </h2>

You might be interested in
K/13 = 0.6/0.5 what does that equal
photoshop1234 [79]
\frac{k}{13} = \frac{0.6}{0.5} equals k = 15.6

First,
simplify \frac{0.6}{0.5} to 1.2. Your problem should look like: \frac{k}{13} = 1.2
Second, multiply both sides by 13. Your problem should look like: k = 15.6, which is the answer.
5 0
3 years ago
G(x)=(x^2+1)(3x-5) what is the value of g(4)?
MAVERICK [17]

g(x) = x^2 + 1(3x - 5)

<em><u>Replace all x's with 4.</u></em>

g(4) = 4^2 + 1(3 * 4 - 5)

g(4) = 16 + 1(12 - 5)

g(4) = 17(7)

g(4) = 119 (This is your answer.)

5 0
3 years ago
Jay sells 10 packs of apples for 80p. He wants to make £75 at the end of the year. How many packs of apples does he need to sell
ipn [44]

Answer:

937.5 packs of apples

Step-by-step explanation:

Note that:

100p = £1

80p = x

Cross Multiply

100x = 80p × £1

x = 80/100

x = £0.8

Jay sells 10 packs of apples for 80p.

Hence:

£0.8 = 10 packs of apples

£75 = x

Cross Multiply

£0.8 × x = £75 × 10 Packs

x = £75 × 10 Packs/£0.8

x = 937.5

Therefore, to make £75 at the end of the year, he has to sell 937.5 packs of apples

3 0
2 years ago
Mrs. Carlyle bought a bag of nuts for her children. Phillip, Joy, Brent, and Preston took some from the bag.Phillip took 1/3. Jo
BARSIC [14]

Answer:

Originally there was 324 nuts in the bag.

Phillip took 108, Joy took 54, Brent took 81 and Preston took 10.

Step-by-step explanation:

Let's call the total amount of nuts N, and the number of nuts each child took by the initial of their name (Phillip will be P1 and Preston will be P2).

So we can write the following equations:

P1 = N/3

After removing N/3, the remaining nuts is (N - N/3):

J = (N - N/3)/4 = (2N/3)/4 = N/6

After removing N/6 from (N - N/3), the remaining nuts is (N - N/3 - N/6):

B = (N - N/3 - N/6)/2 = (N/2)/2 = N/4

P2 = 10

In the final there were 71 nuts remaining, so we have that:

N - N/3 - N/6 - N/4 - 10 = 71

N - N/3 - N/6 - N/4 = 81

N/4 = 81

N = 324 nuts

The amount of nuts took by each child is:

P1 = N/3 = 108 nuts

J = N/6 = 54 nuts

B = N/4 = 81 nuts

P2 = 10 nuts

8 0
3 years ago
What's 49 divided by 261
Tpy6a [65]
.19
Hope this helped!
8 0
3 years ago
Read 2 more answers
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