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boyakko [2]
3 years ago
12

The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is five times

the measure of the first angle. The third angle is 10 more than the second.
Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

first angle be 30°

second angle be 70°

third angle be 80°

Step-by-step explanation:

first angle be x

second angle be y

third angle be z

x+y+z=180

given, y+z = 5x; z=5x-y

also, z=y+10

5x-y = y+10

5x= 10+y+y = 10+2y

x= (10+2y)/5

x+y+z=180

(10+2y)/5 + y + y+10 = 180

(10+2y)/5 = 180 -2y -10

(10+2y)/5 = 170-2y

multiply both sides by 5

10+2y = 5(170-2y)

10+2y= 850-10y

2y+10y = 850-10

12y= 840

y= 840/12 = 70°

z=y+10 =70+10= 80°

5x= (10+2y) = 10+2(70) = 10+140= 150

x = 150/5 = 30°

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Answer:

30%

Step-by-step explanation:

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So, he sold them in 5760

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Studentka2010 [4]

Answer:

x^2 -2x + 1

Step-by-step explanation:

Think of a quadratic equation as

ax^2 + bx + c

x^2 -2x +

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22. Solve 7x - 9 = 28+ 4(x - 1).<br> X=-3<br> X=3<br> x = 11<br> X=-11​
aleksley [76]

Answer:

c) x = 11

Step-by-step explanation:

Given equation: 7x - 9 = 28 + 4(x - 1)

<u><em>Steps:</em></u>

1. Distribute 4 through the parentheses:

7x - 9 = 28 + 4(x) + 4(-1)

7x - 9 = 28 + 4x - 4 [simplify]

7x - 9 = 24 + 4x

2. Subtract 4x from both sides:

7x - 4x - 9 = 24 + 4x - 4x

3x - 9 = 24

3. Add 9 to both sides:

3x - 9 + 9 = 24 + 9

3x = 33

4. Divide both sides by 3:

3x ÷ 3 = 33 ÷ 3

x = 11

5. Check your work:

7x - 9 = 28 + 4(x - 1) [substitute 11 for x]

7(11) - 9 = 28 + 4(11 - 1) [simplify]

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68 = 28 + 40 [add]

68 = 68 ✔

Learn more here:

brainly.com/question/27844321

brainly.com/question/21222758

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Implicit differentiation Please help
Anvisha [2.4K]

Answer:

y''(-1) =8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Quotient Rule: \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

  1. Implicit Differentiation [Product Rule/Basic Power Rule]:                            -y - xy' - 2y' = 0
  2. [Algebra] Isolate <em>y'</em> terms:                                                                               -xy' - 2y' = y
  3. [Algebra] Factor <em>y'</em>:                                                                                       y'(-x - 2) = y
  4. [Algebra] Isolate <em>y'</em>:                                                                                         y' = \frac{y}{-x-2}
  5. [Algebra] Rewrite:                                                                                           y' = \frac{-y}{x+2}

<u>Step 3: Find </u><em><u>y</u></em>

  1. Define equation:                    -xy - 2y = -4
  2. Factor <em>y</em>:                                 y(-x - 2) = -4
  3. Isolate <em>y</em>:                                 y = \frac{-4}{-x-2}
  4. Simplify:                                 y = \frac{4}{x+2}

<u>Step 4: Rewrite 1st Derivative</u>

  1. [Algebra] Substitute in <em>y</em>:                                                                               y' = \frac{-\frac{4}{x+2} }{x+2}
  2. [Algebra] Simplify:                                                                                         y' = \frac{-4}{(x+2)^2}

<u>Step 5: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

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  2. [Derivative] Simplify:                                                                                      y'' = \frac{8}{(x+2)^3}

<u>Step 6: Find Slope at Given Point</u>

  1. [Algebra] Substitute in <em>x</em>:                                                                               y''(-1) = \frac{8}{(-1+2)^3}
  2. [Algebra] Evaluate:                                                                                       y''(-1) =8
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