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3 years ago

Solve equation. 13x + 41 = 16

Mathematics

2 answers:

sveta [45]3 years ago

8 0

Answer:

x = -25/13

Step-by-step explanation:

Subtract 41 from 16 and divide the difference by 13

Artemon [7]3 years ago

7 0

Answer:

$\large\boxed{x=-\dfrac{25}{13}}$

Step-by-step explanation:

$13x+41=16\qquad\text{subtract 41 from both sides}\\\\13x+41-41=16-41\\\\13x=-25\qquad\text{divide both sides by 13}\\\\\dfrac{13x}{13}=\dfrac{-25}{13}\\\\x=-\dfrac{25}{13}$

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Step-by-step explanation:

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Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

$\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0$

Hence, Proved that $\sf \frac{3}{m+4} - \frac{4}{m} = 6$ is equivalent to $\sf 6m^2+25m+16 = 0$ .

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Nikolay [14]

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Step-by-step explanation:

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