Answer:u 2 look sooooooooooo hot ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
Step-by-step explanation:
Answer:
parallel
Step-by-step explanation:
Answer:
3.6
Step-by-step explanation:
<u>Answer:</u>
The 4th term of the geometric sequence with = 5 and ratio (multiplier) = -3 is -135
<u>Solution:</u>
Given that, first term a of a G.P = 5 and common ratio ( r ) = -3 for an geometric progression.
We have to find the 4th term of the above given geometric progression
We know that, nth term of an G.P is given by
![t_{n}=a \cdot r^{n-1}](https://tex.z-dn.net/?f=t_%7Bn%7D%3Da%20%5Ccdot%20r%5E%7Bn-1%7D)
So, now, 4th term is
![\begin{aligned} t_{4} &=5 \times(-3)^{4-1} \\ t_{4} &=5 \times(-3)^{3} \\ t_{4} &=5 \times(-27) \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20t_%7B4%7D%20%26%3D5%20%5Ctimes%28-3%29%5E%7B4-1%7D%20%5C%5C%20t_%7B4%7D%20%26%3D5%20%5Ctimes%28-3%29%5E%7B3%7D%20%5C%5C%20t_%7B4%7D%20%26%3D5%20%5Ctimes%28-27%29%20%5Cend%7Baligned%7D)
![t_{4}=-135](https://tex.z-dn.net/?f=t_%7B4%7D%3D-135)
hence, the 4th term of the given G.P is -135
Answer:
<h3>If a student places in the 99th percentile on an exam , she performed better than
![99\%](https://tex.z-dn.net/?f=99%5C%25)
of all students who completed the exam,Her performance is similar to a statement based on a <u>Cumulative frequency distribution</u></h3><h3>Therefore the Option D) <u>Cumulative frequency distribution </u>is correct.</h3>
Step-by-step explanation:
If a student places in the 99th percentile on an exam , she performed better than
of all students who completed the exam,Her performance is similar to a statement based on a <u>Cumulative frequency distribution</u>
For :
A cumulative frequency plot is a graphical representation with the given data information .
It may be the number, percentage, or proportion of observations that are less than or equal to particular values in the data
<h3>∴ Option D) Cumulative frequency distribution is correct.</h3>