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ki77a [65]
3 years ago
8

What is the 4th term of the geometric sequence with

alt="a_{1}" align="absmiddle" class="latex-formula"> = 5 and ratio (multiplier) = -3?
Mathematics
1 answer:
makvit [3.9K]3 years ago
7 0

<u>Answer:</u>

The 4th term of the geometric sequence with  = 5 and ratio (multiplier) = -3 is -135

<u>Solution:</u>

Given that, first term a of a G.P = 5 and common ratio ( r )  = -3 for an geometric progression.

We have to find the 4th term of the above given geometric progression

We know that, nth term of an G.P is given by

t_{n}=a \cdot r^{n-1}

So, now, 4th term is

\begin{aligned} t_{4} &=5 \times(-3)^{4-1} \\ t_{4} &=5 \times(-3)^{3} \\ t_{4} &=5 \times(-27) \end{aligned}

t_{4}=-135

hence, the 4th term of the given G.P is -135

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