So we are given a system:
Substitute x = 2 we get the system:
Multiply the first equation by -5 and the second by 2 we get the system:
Adding the two equations we get :
We find the value of y by using any of the other equations like this:
Final solution:
You are given two points in the linear function. At time 0 years, the value is $3000. At time 4 years, the value is $250. This means you have points (0, 3000) and (4, 250). You need to find the equation of the line that passes through those two points.
y = mx + b
m = (y2 - y1)/(x2 - x1) = (3000 - 250)/(0 - 4) = 2750/(-4) = -687.5
Use point (0, 3000).
3000 = -687.5(0) + b
b = 3000
The equation is
y = -687.5x + 3000
Since we are using points (t, v) instead of (x, y), we have:
v = -687.5t + 3000
Answer: d. v = -687.50 t + 3,000
Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
Answer:
70%
Step-by-step explananation:
sorry for the previous answer I was thinking u meant something else
Answer:
x = $5.49 cost of the bananas
Step-by-step explanation:
x = cost of the bananas
$3.89 = cost of the peanut butter
$ 9.38 is the cost of both
Bananas + peanut butter = $9.38
x + $3.89 = $9.38
<u> - $ 3.89 = -$3.89 </u> Subtract $3.89 from both sides
x = $5.49
