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Zielflug [23.3K]
3 years ago
14

Graph the image of the figure after a dilation with a scale factor of 14 centered at (5, −5) .

Mathematics
2 answers:
kramer3 years ago
5 0
Check the attached file for the answer. Correction in the problem it is 1/4 not 14.

snow_lady [41]3 years ago
4 0

Given:

Scale factor(k) = 1/4,  and centered at (5, -5).

Labelled the given figure as A, B and C.

The coordinates of the given triangle ABC are;

A = (-3, 7)

B = (-7, -5)

C = (9, 3)

To find the image of the figure after a dilation with scale factor 1/4 centered at (5, -5).

The rule of dilation with scale factor 1/4 and centered at (5, -5) is given by;

(x, y) \rightarrow (\frac{1}{4}(x-5)+5, \frac{1}{4}(y+5)-5)

or

(x, y) \rightarrow (\frac{1}{4}x+\frac{15}{4}, \frac{1}{4}y-\frac{15}{4} )

The coordinates of the image of the figure after dilation are;

A(-3, 7) \rightarrow A'(\frac{1}{4}(-3)+\frac{15}{4}, \frac{1}{4}(7)-\frac{15}{4} )

A(-3, 7) \rightarrow A'(3, -2)

B(-7, -5) \rightarrow B'(\frac{1}{4}(-7)+\frac{15}{4}, \frac{1}{4}(-5)-\frac{15}{4} )

B(-7, -5) \rightarrow B'(2, -5)

and

C(9, 3) \rightarrow C'(\frac{1}{4}(9)+\frac{15}{4}, \frac{1}{4}(3)-\frac{15}{4} )

C(9, 3) \rightarrow C'(6, -3)

As, you can see the graph as shown below in the attachment.

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Solve the following equation |x – 3| = 4. Show all work.
Igoryamba
<h2>Solving Equations with Absolute Values</h2><h3>Answer:</h3>

x = 7 and x = -1

<h3>Step-by-step explanation:</h3>

Solving for the Positive Absolute Value:

|x -3| = 4 \\ x -3 = 4 \\ x -3 +3 = 4 +3 \\ x = 7

Solving for the Negative Absolute Value:

|x -3| = 4 \\ -(x -3) = 4 \\ -(x -3) \cdot -1 = 4 \cdot -1 \\ x -3 = -4 \\ x -3 +3 = -4 +3 \\ x = -1

8 0
3 years ago
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The professor of a business statistics class wanted to find out the average amount of time per week her students spent studying
zhenek [66]

Answer:

Cluster sample

Step-by-step explanation:

This is an example of a cluster sample. In a cluster sample, the examiner divides the population into groups (each one of these groups is called a cluster) and once the examiner has these clusters, takes one of them and recollects the data from ALL the members of that cluster. In this case, the teacher divided the class in 3 different groups and then selects one of these groups and asks the average amount of time per week he/she spent studying.

6 0
3 years ago
A data set is summarized in the frequency table below. Using the table, determine the number of values less than or equal to 6.
Nata [24]

Answer:

18

Step-by-step explanation:

Given the above table of the data set, the number of values less than or equal to 6 would be the sum of the frequencies of all values that is equal to or less than 6.

From the table above, we would add up the frequencies of the values of 6 and below, which is:

2 + 3 + 6 + 4 + 3 = 18

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8 0
3 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

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