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ANTONII [103]
3 years ago
11

Could you guys help me with all 3 pls

Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

1. -5×-5×-5=125

2. 35

3. 22

Step-by-step explanation:

I know the first two are right but unsure about last one.

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Answer:

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Step-by-step explanation:

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True or false. to solve y in the equation 2x y=5, subtract 2 from both sides of the equation
gladu [14]
True. To solve for y you have to subtract 2 from both sides of the equation.
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Write two sets of 5 different numbers that have the same mean but different standard deviations
Zina [86]

Answer:

The sets could be 5, 5, 5, 5, 5 and 0, 10, 20, -10, 5

Step-by-step explanation:

Standard deviations are a measure of how far the average point is away from the mean. In the first example, each term is exactly the mean. In the second set, some are quite a distance from the mean and therefore, it would have a bigger standard deviation.

6 0
3 years ago
Based on the given information, what can you conclude, and why? Given: <H congruent to <L; Line HJ congruent to Line JL
AlexFokin [52]

Answer:

B

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
PLEASE HELP
Ksivusya [100]

Answer:

Option (1)

Step-by-step explanation:

Coordinates of the vertices of a quadrilateral WXYZ drawn in the figure are,

W(-1, 4), X(2, 2), Y(0, -1), Z(-3, 1)

Length of a segment having ends as (x_1, y_1) and (x_2, y_2) is represented by,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of WX = \sqrt{(-1-2)^2+(4-2)^2}

                       = \sqrt{9+4}

                       = \sqrt{13}

Length of XY = \sqrt{(2-0)^2+(2+1)^2}

                      = \sqrt{13}

Length of YZ = \sqrt{(0+3)^2+(-1-1)^2}

                      = \sqrt{13}

Length of ZW = \sqrt{(-1+3)^2+(4-1)^2}

                      = \sqrt{13}

Slope of side WX (m_1) = \frac{y_2-y_1}{x_2-x_1}

                                  = \frac{4-2}{-1-2}

                                  = -\frac{2}{3}

Slope of side XY (m_2) = \frac{2+1}{2-0}

                                    = \frac{3}{2}

By the property of perpendicular lines,

m_1\times m_2=-1

(-\frac{2}{3})(\frac{3}{2})=-1

therefore, WX and XY are perpendicular.

Slope of YZ (m_3) = \frac{-1-1}{0+3}=-\frac{2}{3}

m_2\times m_3=(\frac{3}{2})\times (-\frac{2}{3})=-1

Therefore, XY ⊥ YZ

Similarly, we can prove YZ ⊥ ZW.

Therefore, quadrilateral WXYZ is a SQUARE.

Option (1) will be the answer.

7 0
3 years ago
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