Answer:
The price of the cake is $24 and the price of the Pie is $15
Step-by-step explanation:
Given
<em>Represent price of Cake with C and Price of Pie with P</em>

Cakes sold = 8
Pies sold = 14

Required
Determine C and P
To represent the cakes and pies sold, we have the following expression

Substitute 9 + P for C

Open the bracket

Collect Like Terms


Divide both sides by 22


Recall that



<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>
Answer: Area of ΔABC is 2.25x the area of ΔDEF.
Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

with a as side of the triangle.
Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:
a₁ = 1.2a
Then, its area is


Triangle DEF is 20% smaller than the original, which means its side is:
a₂ = 0.8a
So, area is


Now, comparing areas:

2.25
<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>