Can someone help me pls 10 points
2 answers:
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<h2>Answer with explanation:</h2>
We know that a removable discontinuity occurs when:
The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.
Also it is a point on the graph such that it is undefined at that point.
The graph that has a removable discontinuity is attached to the answer.
Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.
Answer:
Step-by-step explanation:
In the table, they give you an x-value. Use the x-value to solve for y. You will then get a point. Plot the points to find the graph.
y = 1/2x
y = 1/2(0)
y = 0
(0, 0)
y = 1/2x
y = 1/2(2)
y = 1
(2, 1)
y = 1/2x
y = 1/2(-4)
y = -2
(-4, -2)
