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2 years ago

Evaluate the function: f(x)=4x−2, find f(8)

Mathematics

1 answer:

valina [46]2 years ago

4 0

Answer:

f (8) = 30

Step-by-step explanation:

$f(x)=4x-2\\\\f(8)=4(8)-2\\\\f(8)=32-2\\\\\boxed{f(8)=30}$

Hope this helps.

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the seating capacity of basketball stadium is 5782 the seats are arranged in 24 sections of the same size any seats over from th

notsponge [240]

5782/24=240 since we round down to s whole.

Multiply again by 24.
240*24=5760

There are 5782-5760=22 priority seats.

The correct answer is 22.

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2 years ago

help Bob divide his water plants for the outer four aquariums. Insert images of the plant in the space below to show how you can

dexar [7]

Answer:

The Answer is 4.5 or 4 1/2

Step-by-step explanation:

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2 years ago

Using the answers from z^4=16 determine the solutions of the equation (x+1)^4=16(x-1)^4

Artemon [7]

i hope i have been useful buddy.

good luck ♥️♥️♥️♥️♥️.

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2 years ago

Please help me answer a and b please

quester [9]

Answer:

for question a Tom is working at a faster pace because he is currently installing 7 windows a day while Suzanne is only installing 6 windows per day.

for question b Suzanne started off with more windows installed. I know this because the equation says that tom started with 3 windows installed and suzanne started with 5 windows installed.

Step-by-step explanation:

3 0

2 years ago

A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base

Aliun [14]

Answer:

$2\ cm$

Step-by-step explanation:

$We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224= \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h$

$As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel$

$Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm$

8 0

2 years ago