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3 years ago

A + 3y + 4a - 2y + 10

Mathematics

1 answer:

Galina-37 [17]3 years ago

8 0

Answer:

5a+y+10 is your answer

Step-by-step explanation:

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Pleaseeee help!!!!!!!! I will mark you as brainlinest for correct answer!!!!!!!!!!

user100 [1]

Let x be the cost of gum 20 years ago.
3x - 3 = 75
3x = 78
X = 78/3
X = 26.
So the write answer is A) 3x - 3 = 75.

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3 years ago

What angle is complementary to 1 ? I'll mark brainliest

Marat540 [252]

The angle complementary to angle 1 is angle 2

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3 years ago

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Please help!!!!!!!!!!!!!

jonny [76]

Answer:

The answer to your question is (2,12). Hope you have a nice day.

Step-by-step explanation:

So, first you put in the x value. 8(2)-y=4, 16-y=4. Then you subtracted 4 from each side. 4-4=0 and 16-4=12. 16-12=4.

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3 years ago

What is the mean absolute deviation of 140,115,190,205,120,140,160,200,210,190

Lisa [10]

Answer: population size= 10

Mean= 167

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Step-by-step explanation:

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3 years ago

Customers arrive at a bank drive-up window every 6 minutes based on a Poisson distribution. Once they arrive at the teller, serv

Jet001 [13]

Answer:

(a) 0.01029 (b) 4.167 customers (c) 0.4167 hours or 25 minutes (d) 0.5 hours or 30 minutes

Step-by-step explanation:

With an arrival time of 6 minutes, λ=10 clients/hour.

With a service time of 5 minutes per transaction, μ=12 transactions/hour.

(a) The probability of 3 or fewer customers arriving in one hour is

P(C<=3)=P(1)+P(2)+P(3)

$P(X)=\lambda^{X}*e^{-\lambda} /X!$

$P(1)=10^{1}*e^{-10} /1!=0.00045\\P(3)=10^{3}*e^{-10} /3!=0,00227\\P(2)=10^{2}*e^{-10} /2!=0,00757\\P(x\leq3)=0.00045+0.00227+0.00757 = 0.01029$

(b) The average number of customers waiting at any point in time (Lq) can be calculated as

$L_{q}=p*L=\frac{\lambda}{\mu}*\frac{\lambda}{\mu-\lambda}\\L_{q}=\frac{10}{12}*\frac{10}{12-10}\\\\L_{q}=100/24=4.167$

$W_{q}=p*W=\frac{\lambda}{\mu}*\frac{1}{\mu-\lambda}\\W_{q}=(10/12)*(1/(12-10))\\W_{q}=(10/24)=0.4167$

(d) The average time in the system (W), waiting and service, can be calculated as

$W=\frac{1}{\mu-\lambda}\\W=\frac{1}{12-10}=0.5$

6 0

3 years ago