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mylen [45]
2 years ago
10

The volume of Mikes rectangular lunch box is 240 cubic inches. The lunchbox is 3 inches deep and its length is 2 inches more the

n its width. What is the width of Mike's lunchbox
Mathematics
1 answer:
allochka39001 [22]2 years ago
6 0

Answer:

8 inches

Step-by-step explanation:

You first divide 240 by 3 which is 80

Then you find what number is 2 less than the other number that is you multiplied together you get 80

And we know that 8 × 10 = 80

There for the :-

Width is 8 in

Length is 10 in

Hight is 3 in

The proof is if you multiply all of them you have to get 240

And if you multiply 8, 10, and 3 you get 240

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Complementary angles add up to 90 so 90-29=the complement, which is 61.
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A model car has a scale factor of 1/64 The diameter of a tire on the model is 0.39 inches. So, the diameter of the tire on an ac
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3 years ago
Need help on this please I would really appreciate it :)
sdas [7]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
Billy is on a weekend fishing trip with his scout troop. So far he has caught 4 trout and 10 catfish. What is the probability th
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6 0
4 years ago
What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

7 0
3 years ago
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