Find the area of the image below: Figure ABCDE is shown. A is at 6, 0. B is at negative 4, 5. C is at 2, 5. D is at 2, 9. E is a
t 6, 9. 41 square units 44 square units 52 square units 56 square units
2 answers:
<h2>Answer:</h2>
The area of image is: 41 square units
<h2>Step-by-step explanation:</h2>The area of the image is equal to:
Area of square CDEF+Area of right angled triangle ΔBFA
In square CDEF we have:
The lengths of the side of the square= 4 units
Hence, the area of square is: side²
i.e. Area of square= 4²=16 square units
Also, in ΔBFA we have:
The base of the triangle is: BF=CB+CF=6+4= 10 units
Also, height of the triangle is: FA= 5 units
Hence, we have area of ΔBFA as:
Area= 1/2×BF×FA
i.e.
Area= 1/2×10×5
i.e.
Area= 25 square units
Hence, the area of image is: 16+25
i.e.
Area of image= 41 square units
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