Answer:
int k = 1;
int total = 0;
while (k <= n){
total = total + (k*k*k);
k++;
}
Explanation:
The code above has been written in Java.
Following is the line-by-line explanation of the code written as comments.
// Initialize int variable k to 1.
// variable k is used to control the loop.
// It is initialized to 1 because the positive integers should start at 1.
// Starting at zero will be unimportant since the cube of 0 is still zero and
// has no effect on the overall sum of the cubes.
int k = 1;
// Initialize total to zero(0)
// This is so because, at the start of the addition total has no value.
// So giving it zero allows to cumulatively add other values to it.
// Variable <em>total </em>is also of type int because the sum of the cubes of counting
// numbers (which are positive integers) will also be an integer
int total = 0;
// Now create a while loop to repeatedly compute the sum of the cubes
// while incrementing the counter variable <em>k</em>.
// The condition for the loop to execute is when <em>k</em> is less than or equal to
// the value of variable <em>n.</em>
// The cube of any variable k is given by which can be
// written as k * k * k.
// At every cycle of the loop, the cube of the counter <em>k</em> is calculated and
// added cumulatively to the value of <em>total</em>. The result is still stored in the
// variable <em>total. </em>After which <em>k</em> is incremented by 1 (k++).
while (k <= n) {
total = total + (k*k*k);
k++;
}
