Answer:
i think images are converted into digital forms because i dont know
This is an example of <u>b2b</u> customer service.
<u>Explanation:</u>
B2b customer service is the customer service which stands for business to business. It refers to the sale that you make to the business instead of an individual consumers.
B2b customer experiences include creating a personalized. omni channel experience and building lasting relationships while providing convenient, digital solutions.
Answer:
Sensitivity
Explanation:
He is most likely going into sensitivity because he is trying to send a private message.
Answer:
The program in C++ is as follows:
#include<bits/stdc++.h>
using namespace std;
class Complex {
public:
int rl, im;
Complex(){ }
Complex(int Real, int Imaginary){
rl = Real; im = Imaginary;
}
};
int main(){
int real, imag;
cout<<"Real: "; cin>>real;
cout<<"Imaginary: "; cin>>imag;
Complex ComplexNum(real, imag);
cout<<"Result : "<< ComplexNum.rl<<" + "<<ComplexNum.im<<"i"<<endl;
}
Explanation:
See attachment for explanation
Answer:
Explanation:
The following program is written in Java. The main method asks the user to enter 10 different integer values. These values are saved to an integer array and passed to the SelectionSortDescendTrace() method. This method sorts the array in descending order while printing the entire array after every outer loop cycle. The program was tested and the output can be seen in the attached image below.
import java.util.*;
class Brainly {
// Main Method
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
int[] myArr = new int[10];
for (int i = 0; i < 10; i++) {
System.out.print("Enter an integer: ");
myArr[i] = in.nextInt();
System.out.print('\n');
}
SelectionSortDescendTrace(myArr);
}
public static void SelectionSortDescendTrace(int[] myArr) {
int temp;
for (int i = 0; i < myArr.length; i++)
{
for (int j = 0; j <myArr.length; j++)
{
if (j != myArr.length - 1)
{
if (myArr[j] < myArr[j + 1])
{
temp = myArr[j];
myArr[j] = myArr[j + 1];
myArr[j + 1] = temp;
}
}
}
System.out.println(Arrays.toString(myArr));
}
}
}