Answer:
he spent $16.5
Step-by-step explanation:
There are 6! = 720 ways of arranging the lamps.
If the leftmost lamp is red, there are 3 choices of lamp in the leftmost position, and the remaining 5 can be placed in any order, so there are 3×5! = 360 ways of arranging the lamps and the leftmost is red.
Hence there is a 360/720 = 1/2 probability that the leftmost lamp is red.
Ignoring lamp color for the moment, the probability of arranging 3 lit lamps and 3 unlit lamps is the same, 1/2.
Since Ryan arranges the lamps randomly by color, then turns 3 of them on randomly, the two events are independent. So
P(leftmost red AND leftmost lit) = P(red) × P(lit) = 1/2² = 1/4
Answer:
<h2>Sf - 3</h2><h2>PSf - 2</h2><h2>SIf - 1</h2><h2>Nf - 4</h2>
Step-by-step explanation:
1.) 5+4/7(21+3x)=41
5+ 12+12/7x= 41
12/7x= 41-12-5
12/7x= 24
x= 24/ (12/7)
x=14
2.) x+15.09= -2.57
x = -2.57-15.09
x= -17.66
The largest rational number in the list is -6/5 and it is the third number line.
