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3 years ago

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Mathematics

1 answer:

valina [46]3 years ago

6 0

I think 28fa haha s an

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IF YOU DO IT THEN YOU WILL GET BRAINLIEST! −9x+4y=6 9x+5y=−33 SOLVE FOR X AND Y

BigorU [14]

Answer:

x = 2 y = 3

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

7 0

3 years ago

Find the diagonal of a square whose sides are of the given measure. Given = 6"

ikadub [295]

Answer:

subscribe to me on you-tube for brainliest custom link since u cant do a you-tube link :/

https://screenshare.host/B7N8NT

Step-by-step explanation:

3 0

3 years ago

I need this help me please

Montano1993 [528]

Answer:

Step-by-step explanation:

They are both straight lines. Function A has slope -5

Function B has slope -4.5

-4.5 > -5

B has the greater rate of change.

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3 years ago

Solve x TN = 8 nV =x - 2?

AleksandrR [38]

Answer:

Step-by-step explanation:

STUV is a parallelogram.

TV and SU are its diagonals intersecting at point N.

Diagonals of a parallelogram bisects each other.

Therefore, TN = NV

8 = x - 2

8 + 2 = x

10 = x

x = 10

7 0

3 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

4 0

3 years ago