3x^2-18+5=47
3x^2 = 60
x^2 = 20
x = 4.472 , x = - 4.472
0.10d + 0.25q = 3.55
q = d + 3
0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes
q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters
2³ + 3² = 2*2*2+3*3= 8+9=17
a=2,
b=3,
P= 17,
2,3,17 are all prime numbers
Answer:
C. 3/4 and 6/8
<em>good luck, i hope this helps :)
</em>
Answer:
Kindly check explanation
Step-by-step explanation:
Kilogram of flour needed to complete holiday order is atleast 175kg
Number of kilograms available = 34kg
Flour comes in bags each contain 23kg of flour
He wants to buy the smallest number of bags as possible and get the amount of flour he needs.
Let F = number of bags of flours Sergei needs to buy
F = (total number of kilograms needed - number of kilograms available) / kilograms per bag
F = (≥ 175 - 34) / 23
F = ≥ 141 / 23 = ≥ 6.1304347
Since flour is purchased per bag, the smallest number of bags he can possibly buy and still get the amount of flour he need = 7 bags
