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MrMuchimi
2 years ago
10

what's 77787464564576876979875648366732783656938629312935o5193865435986581653195395619856589316589346531713683586982635 x 473853

98363630636386392032903395360 - 54464777575666666666666665
Mathematics
2 answers:
blsea [12.9K]2 years ago
5 0

Answer:

Ask Albert Einstein

Step-by-step explanation:

There is an o, and don't know why there is an o.

what's 77787464564576876979875648366732783656938629312935<u>o</u>5193865435986581653195395619856589316589346531713683586982635 x 47385398363630636386392032903395360 - 54464777575666666666666665

Marizza181 [45]2 years ago
3 0

Answer:

3.68599e+145

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Every _____ tessellates.<br> A. Decagon<br> B. Polygon<br> C. Triangle<br> D. Hexagon
olga2289 [7]
The answer is letter B. Every polygon tesselates. Since the word 'tesselate' here means a pattern of shapes put together without any gaps, then I think every polygon tesselates if they are put side by side together in varying amounts and leave absolutely no gaps or spaces between each other.
8 0
3 years ago
Tim buys a torch and battery the torch costs 11 times as much as the battery Tim pays with a ?10 note and he gets ?4.84 change h
KengaRu [80]

The cost of 1 battery is 0.43

Step-by-step explanation:

Let the cost of 1 battery be x

We are given that the torch costs 11 times as much as the battery

Cost of torch = 11x

Total cost of 1 battery and torch = 11x+x=12x

Tim pays $10

He receives change of $4.84

Total cost of 1 torch and battery = 10 - 4.84 =$5.16

So,12x= 5.16

x= \frac{5.16}{12}

x=0.43

Hence the cost of 1 battery is 0.43

6 0
3 years ago
Doug, a student in this class, knows how to write programs in JAVA. Everyone who knows how to write programs in JAVA can get a h
In-s [12.5K]

Missing Part of Question

Explain which rules of inference are used in the above

Answer:

Universal instantiation, Modus ponens and Existential generalization

Step-by-step explanation:

Splitting the Statement into two, we have

"Doug knows how to write program is Java"

and

"Doug can get a high paying job"

Represent Doug with x. Then the statements is rewritten as

P(x) = "x knows how to write program is Java"

and

Q(x) = "x can get a high paying job"

In logic, A premise is a statement in an argument that provides reason or support for the conclusion.

So, Statement 1 can be written as

1. P(x) ---- Premise

Then, we have

2. Vx(P(x) --> Q(x)) -- Premise. This mean that P(x) for all values in the domain.

The universal instantiation of (2) leads to

3. P(Doug) --> Q(Doug)

The modus ponens of the above gives

4. Q(Doug)

The existential generalisation from above gives

5. ƎxQ(x)

Which means someone in this class can get a high paying job.

PS:

Universal Instantiation is a valid rule of inference from a truth about each member of a class of individuals to the truth about a particular individual of that class; it is represented by VxP(x).

Existential Generalisation is a valid rule of inference that allows one to move from a specific statement, or one instance, to a quantified generalized statement, or existential proposition.

It is represented as ƎxP(x)

4 0
3 years ago
Use substitution to solve the following system of equations. What is the value of y? {3x+2y=12{5x−y=7 A) y = -3B) y = 3C) y = -2
Vlad [161]

<em>Answer</em>

B) y = 3

<em>Step-by-step explanation</em>

Given the system of equations:

\begin{gathered} 3x+2y=12\text{ \lparen eq. 1\rparen} \\ 5x-y=7\text{ \lparen eq. 2\rparen} \end{gathered}

Isolating x from equation 1:

\begin{gathered} 3x+2y-2y=12-2y \\ 3x=12-2y \\ \frac{3x}{3}=\frac{12-2y}{3} \\ x=\frac{12}{3}-\frac{2}{3}y \\ x=4-\frac{2}{3}y\text{ \lparen eq. 3\rparen} \end{gathered}

Substituting equation 3 into equation 2 and solving for y:

\begin{gathered} 5(4-\frac{2}{3}y)-y=7 \\ 5\cdot4-5\cdot\frac{2}{3}y-y=7 \\ 20-\frac{10}{3}y-y=7 \\ 20-\frac{13}{3}y=7 \\ 20-\frac{13}{3}y-20=7-20 \\ -\frac{13}{3}y=-13 \\ (-\frac{3}{13})\cdot-\frac{13}{3}y=(-\frac{3}{13})\cdot-13 \\ y=3 \end{gathered}

6 0
1 year ago
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bogdanovich [222]

Answer:

(A) - (5)

(B) - (4)

(C) - (1)

(D) - (2)

Step-by-step explanation:

(A) We are given the polynomial (x+4)(x−4)[x−(2−i)][x−(2+i)]

(5) The related polynomial equation has a total of four roots; two roots are complex and two roots are real.

(B) We are given the polynomial (x+i)(x−i)(x−2)³(x−4).

(4) The related polynomial equation has a total of six roots; two roots are complex and one of the remaining real roots has a multiplicity of 3.

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(1) The related polynomial equation has a total of four roots; all four roots are real and one root has a multiplicity of 2.

(D) We are given the polynomial (x+2)²(x+1)²

(2)  The related polynomial equation has a total four roots; all four roots are real and two roots have a multiplicity of 2. (Answer)

8 0
3 years ago
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