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Anuta_ua [19.1K]
3 years ago
11

Write the equation of the line that passes through the points (-7,-9) and (-3,-1)

Mathematics
2 answers:
zysi [14]3 years ago
3 0

Answer:

2x + 5

Step-by-step explanation:

I am assuming you are talking about a linear function. If it is, then the equation would be:

2x + 5.

Hope this helps!

Dahasolnce [82]3 years ago
3 0

Answer:

y = 2x + 5

Step-by-step explanation:

For this example, I used the slope-intercept form, y = mx + b, where m represents the slope and b represents the y-intercept.

In order to find the equation, we must find the slope and y-intercept.

<h3>Finding m</h3>

The slope can be found with the formula:

m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}, where the x and y variables represent different x and y values from the given points.

Substituting in values from the points, we get:

m = \frac{-1 + 9}{-3 + 7}\\\\m = \frac{8}{4}\\\\m = 2

<h3>Finding b</h3>

In order to find the y-intercept, we must substitute the slope back into the original equation:

y = 2x + b

After this, we must also substitute either of the two points. Both will give the correct answer, but (-3, -1) will be used for this example.

-1 = 2(-3) + b\\-1 = -6 + b\\5 = b

<h3>Finding the equation</h3>

After this, all that must be done is to substitute the values for b and m back into the original equation.

y = 2x + 5

To check our work, we can substitute in either of the given points. For demonstration purposes, (-7, -9) will be used.

(-9) = 2(-7) + 5\\-9 = -14 + 5\\-9 = -9

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A certain manufacturing company has the following data on quantities shipped and unit costs for each of its four products.
AnnyKZ [126]

Answer:

Paasche's Index=  168.63= 169

Step-by-step explanation:

<em><u>Products</u></em>

<em><u>Base-Period                                                    Current Period</u></em>

    Quantities    Mean Shipping                    Quantities    Mean Shipping

     (Year 1)         Cost per Unit ($)                  (Year 5)  Cost per Unit ($)

A         1,500         10.50                         4000                 15.90

B         5,000      16.25                            3000                 33.00

C         6,500        12.20                          8000                  18.40

D          2,500      20.00                         3000                   35.50

Paasche's Index= ∑ pn.qn/∑po.qn* 100

Where pn is the price of the current year and qn is the quantity of the current year and po. is the price of the base year and qo. is the quantity of the base year.

Paasche's Index is the percentage ratio of the aggregate of given period prices weighted by the quantities sold or consumed in the given period to the aggregate of the base period prices weighted by the given period quantities.

Multiplying the current year prices with the current year quantities and the base year price with the current year quantities we get.

Product               pn.qn                      po.qn

A                         15.90* 4000         10.50* 4000

                          = 63600                    =42000

B                       33.00*3000           16.25 * 3000  

                           = 99000                    = 48750

C                      18.40* 8000          12.20 *8000

                            =147200                 =97600

D                     35.50* 3000        20.00*3000  

<u>                           =</u><u>106500              60,000   </u><u>       </u>

<u>∑                          416300                  248350       </u>

<u />

Paasche's Index= ∑ pn.qn/∑po.qn= <u> </u>416300/ 248350 *100  =  1.676=1.68= 168.63= 169

<u />

7 0
3 years ago
Find the area between the two functions
Inga [223]

The area between the two functions is 0

<h3>How to determine the area?</h3>

The functions are given as:

f₁(x)= 1

f₂(x) = |x - 2|

x ∈ [0, 4]

The area between the functions is

A = ∫[f₂(x) - f₁(x) ] dx

The above integral becomes

A = ∫|x - 2| - 1 dx (0 to 4)

When the above is integrated, we have:

A = [(|x - 2|(x - 2))/2 - x] (0 to 4)

Expand the above integral

A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]

This gives

A = [2 - 4] - [-2- 0]

Evaluate the expression

A = 0

Hence, the area between the two functions is 0

Read more about areas at:

brainly.com/question/14115342

#SPJ1

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GrogVix [38]

Answer:

i would say 18/24

Step-by-step explanation:

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Levart [38]

Answer:

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zlopas [31]

Answer:

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Step-by-step explanation:

i need more of the problem though

6 0
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