Question

Please Help!! I will give brainliest The question is attached below

Answer 1

Answer:

Step-by-step explanation:

P(x) = $\frac{2}{3x-1}$

Q(x) = $\frac{6}{-3x+2}$

P(x) × Q(x) = $\frac{2}{3x-1}\times \frac{6}{-3x+2}$

                 = $\frac{2\times 6}{(3x-1)(-3x+2)}$

                 = $\frac{12}{(3x-1)(-3x+2)}$

P(x) ÷ Q(x) = $\frac{2}{(3x-1)}$ ÷ $\frac{6}{(-3x+2)}$

                 = $\frac{2}{(3x-1)}\times \frac{(-3x+2)}{6}$

                 = $\frac{(-3x+2)}{3(3x-1)}$