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krek1111 [17]
3 years ago
6

Can someone help me with this math problem ​

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
8 0

Answer:

5370

Step-by-step explanation:

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Determine the value of f (4) if f (x) = 3x -- 1
sleet_krkn [62]

Answer: 11

Step-by-step explanation: plug in 4 for x

3(4) - 1 = 12 - 1 = 11

4 0
3 years ago
PLZ ANSWER ASAP!! THANK YOU ​
evablogger [386]

Answer:

5 1/4

Step-by-step explanation:

cause if you multiply those numbers you should get the answer

Glad i can help!!!

8 0
2 years ago
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Is /1.33 a rational number
SpyIntel [72]
Yes, it is a rational number.
6 0
2 years ago
Find the geometric mean of the pair of numbers
Svetach [21]

Answer: a. 55

Step-by-step explanation:

The formula to find the geometeric mean between two numbers a and b is given by :-

G.M. =\sqrt{ab}

The given numbers are : 275 and 11

The geometric mean of 275 and 11 is given by :-

G.M.=\sqrt{275\times11}\\\\\Rightarrow\ G.M. =\sqrt{3025}\\\\\Rightarrow\ G.M.=\sqrt{55\times55}\\\\\Rightarrow\ G.M.=\sqrt{55^2}\\\\\Rightarrow\ G.M.=55

Hence, the geometric mean of 275 and 11 is 55.

So , the correct option is a. 55 .

4 0
2 years ago
The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,
strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=400 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=80 represent the population standard deviation

n=15 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

400-2.58\frac{80}{\sqrt{15}}=346.708    

400+2.58\frac{80}{\sqrt{15}}=453.292

So on this case the 99% confidence interval would be given by (346.708;453.292)    

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that t_{\alpha/2}=2.98

Now we have everything in order to replace into formula (1):

400-2.98\frac{80}{\sqrt{15}}=338.445    

400+2.98\frac{80}{\sqrt{15}}=461.555

So on this case the 99% confidence interval would be given by (338.445;461.555)    

4 0
2 years ago
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