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2 years ago

7

I need helpppppppppppppp please

1 answer:

jok3333 [9.3K]2 years ago

7 0

It’s be because I took that same answer and I know it’s b so yeah

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Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to:

$\mu-2\sigma = 22.32 - 2(4.1186) = 14.0828 \approx 14.08\\\\\mu+2\sigma = 22.32 + 2(4.1186) = 30.5572 \approx 30.56$

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3 years ago

4p + 8 - 3p - 2

kozerog [31]

Well that friend should write p + 6 after combining like terms and simplifying

6 0

2 years ago

Five plus three equals

8_murik_8 [283]

Answer: 8

Step-by-step explanation:

5

+

3

8

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5 0

3 years ago

Read 2 more answers

Thomas is throwing a graduation party for his son Michael. He went to the store and bought a total of 34 apples. The number of g

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8 0

2 years ago

Please help! Brainliest

Mama L [17]

1.301

Explanation:

Given:

$\log_a5 \approx 0.699$ and $\log_a2 \approx 0.301$

Note that from the properties of logarithms,

$\log_a20 = \log_a(5×4)$

$\:\:\:\:\:\:\:\:\:\:= \log_a(5×2^2)$

$\:\:\:\:\:\:\:\:\:\:=\log_a5 + \log_a(2)^2$

$\:\:\:\:\:\:\:\:\:\:=\log_a5 + 2\log_a2$

$\:\:\:\:\:\:\:\:\:\:\approx 0.699 + 2(0.301)$

$\:\:\:\:\:\:\:\:\:\:= 1.301$

6 0

2 years ago