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Natalka [10]
3 years ago
7

Because of the increasing nuisance of spam e-mail messages, many start-up companies have emerged to develop e-mail filters. One

such filter was recently advertised as being 95% accurate. This could mean one of four things.
(a)95% of the email allowed through is valid,
(b)95% of spam is blocked,
(c) of the blocked e-mail is spam, or
(d) 95% of valid e-mail is allowed through
Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

B. 95% of spam is blocked.

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Evaluate the statistics expression:39C1
Aleksandr-060686 [28]
<h3>Answer:  39</h3>

========================================================

Explanation:

You can use the nCr formula shown below

_n C _r = \frac{n!}{r!*(n-r)!}

where n = 39 and r = 1. However, you could also use the identity

_n C _{1} = n

which basically says there are n ways to pick 1 item if you are given a choice of n items. In this specific case, we have 39 items total, and there are 39 ways to pick one item.

4 0
3 years ago
Kjnhbgvnfcbvhjnkml,;'.<br> ?}{:HJUbmgfcbdxvsc
Sergio [31]

Answer:

$3 for 1 book.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
(25 points) A weather reporter in your area said that the speed of sound in air today is about one thousand one hundred feet per
Rashid [163]
1 thousand and 1 hundred means 1100. 

In scientific notation, it's 1.1*10^3
6 0
3 years ago
Read 2 more answers
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
Which pair of ratios are equal?6/15 and 3/17 3/4 and 9/11 2/5 and 12/35 or 2/3 and 8/12
Elanso [62]
The last pair.
Because 2*4/3*4=8/12
7 0
4 years ago
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