Question

In ΔFGH, the measure of ∠H=90°, FH = 8, OF = 17, and HG = 15. What ratio represents the sine of ∠G?

Answer 1

Answer:

$\sin(G) = \frac{8}{17}$

Step-by-step explanation:

Given

$\angle H = 90^o$

$FH = 8$

$GF = 17$

$HG = 15$

See attachment for illustration

Required

The ratio of $\sin(G)$

$\sin(G)$ is calculated as:

$\sin(G) = \frac{Opposite}{Hypotenuse}$

From the attachment, we have:

$\sin(G) = \frac{FH}{GF}$

This gives:

$\sin(G) = \frac{8}{17}$