Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
Answer:
14 & 16
Step-by-step explanation:
30÷2=15
15+15=30, so we can make the conclusion...
14+16=30
From the information: v is 64 while c is 5
Differentiate the new equation h=-16
+ 64t + 5 to get
= -32t + 64.
no 13). At maximum height this derivative equals zero so: -32t + 64 = 0; -32t = -64; t=2.Hence ans is 2 secs
no 14). put t as 2 sec in the equation: h=-16
+ 64t + 5. This gives
h=-16(
) + 64(2) + 5; h=-64+128+5=69. Hence h is 69ft