All categories

3 years ago

Can someone answer this i don't understand it

Mathematics

1 answer:

Lena [83]3 years ago

5 0

Based on my understanding, it’d be 32 2/3 since you’d multiply based on what’s the chart, example being 4 times 8 and 4 times 1/6

You might be interested in

I need help with my math, please?

jok3333 [9.3K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Max spends three times as long on his math homework than he does on his science homework. If he spent total of 64 minutes on mat

den301095 [7]

Let X = science homework.

Then math homework would be 3x ( three times as long).

Now you have math plus science = 64 minutes:

x + 3x = 64

Combine like terms:

4x = 64

Divide both sides by 4:

x = 64 / 4

x = 16

He spent 16 minutes on science and 48 minutes on math.

6 0

3 years ago

LOAD OF QUESTIONS:

Law Incorporation [45]

the end behavior of the function f(x)

the function f(x) must has odd number of roots ( where the graph of a function intersects the x-axis

the width cant be negative so the width of the rectangle would be 8 inches

4 0

3 years ago

Read 2 more answers

As a member of a music club, you can order CDs for $14.99 each. The music club also charges $4.99 for each shipment. The express

KATRIN_1 [288]

I hope this helps you

6 0

4 years ago

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

3 years ago