Question

NEED HELP ASAP!!! PLEASE!!!

Answer 1

From Daniel's initial location from the campsite given the width of the

stream is 400 feet and Daniel swims to the boat ramp, we have;

1.) Please find attached the drawing of the situation

2.) 3.34 minutes

3.) 1,298.59 feet

4.) 3.69 minutes

How can the distances and times be calculated?

1.) Please find attached a labelled diagram of the scenario created with MS Visio

2.) Daniel's average swimming rate (speed) = 150 feet per minute

$The \ distance \ Daniel \ swims = \mathbf{\dfrac{400 \, feet}{sin(53^{\circ})}} \approx 500.85 \, feet$

The time it takes him to swim to the boat ramp, t, is therefore;

• $t \approx \dfrac{500.85 \ feet}{150 \ feet/min} \approx \underline{3.34 \ minutes}$

3.) The distance, d₁, downstream of the boat ramp from Daniel is given as follows;

d₁ = √((500.85 feet)² - (400 feet)²) ≈ 301.41 feet

Therefore;

The distance from the boat ramp to the campsite, d₂, is therefore;

d₂ ≈ 1600 feet - 301.41 feet = 1,298.59 feet

The distance from the boat ramp to the campsite, d₂ ≈ 1,298.59 feet                              

4. The time, t₂, it will take Daniel to jog from the boat ramp to the campsite is given as follows;

$t_2 = \mathbf{\dfrac{d_2}{v_2}}$

Where;

v₂ = The rate at which Daniel can jog, which is 4 mph

Which gives;

$t_2 = \mathbf{\dfrac{1298.59 \, feet}{4 \, mph}} = \dfrac{1298.59 \, feet}{4 \, mph} \approx \dfrac{1298.59 \, feet}{5.866142 \ feet/s} \approx \dfrac{221.37 \, s}{60 \, s/min} \approx 3.69 \, min$

Therefore;

• The time it takes him to jog from the boat camp to the campsite, t₂ ≈ 3.69 minutes

Learn more about Pythagorean theorem here:

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