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3 years ago

Help me! PLEASE! help help help help help help help help help help help help!!!!!!

Mathematics

1 answer:

rjkz [21]3 years ago

7 0

Sara's results probably do have a higher mean, if we take into account how William is way more willing to pay 20 dollars. Honestly, I think you got your chosen answers right! Just my opinion, as someone inexperienced.

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Find the exact volume of the cylinder.<br> 1471 m3<br> 2871 m3<br> 5670 m3<br> 11271 m3

jenyasd209 [6]

Answer:

hmmmm........

Step-by-step explanation:

radius is 4/2=2m

volume of the cylinder is equal

to πr^h

i.e, π(2m)^2×7m

≈88 m^3

3 0

3 years ago

Which statement is not always true for a parallelogram?

VARVARA [1.3K]

<h3>Answer: B. Diagonals are congruent.</h3>

Explanation:

If the diagonals are congruent, then we'd have a rectangle. Any rectangle is a parallelogram, but not the other way around.

If we had a non-rectangular parallelogram, with none of the angles 90 degrees, then the diagonals will not be the same length.

Choices A, C and D are true for any parallelogram (rectangle or not).

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3 years ago

What is 11/12 minus 7/9 equal

julia-pushkina [17]

Answer:

5/36

Step-by-step explanation:

We need the least common denominator for 12 and 9.

12 = 2^2 * 3

9 = 3^2

LCD = 2^2 * 3^2 = 4 * 9 = 36

11/12 - 7/9 = 33/36 - 28/36 = 5/36

5 0

3 years ago

Z-scoreAn organization collects information on the production and consumption of food and agriculture products for 200 countries

kati45 [8]

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4 years ago

State the vertical asymptote of the rational function. f(x) =((x-9)(x+7))/(x^2-4)

Lubov Fominskaja [6]

$D:x^2-4\not=0\\
D:x^2\not=4\\
D:x\not=-2 \wedge x\not =2\\\\
\displaystyle
\lim_{x\to-2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(-2-9)(-2+7)}{(-2^-)^2-4}=\dfrac{-11\cdot5}{4^+-4}=\dfrac{-55}{0^+}=-55\cdot\infty=-\infty\\
\dfrac{(-2-9)(-2+7)}{(-2^+)^2-4}=\dfrac{-11\cdot5}{4^--4}=\dfrac{-55}{0^-}=-55\cdot(-\infty)=\infty
$

$\displaystyle
\lim_{x\to2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(2-9)(2+7)}{(2^-)^2-4}=\dfrac{-7\cdot9}{4^--4}=\dfrac{-63}{0^-}=-63\cdot(-\infty)=\infty\\
\dfrac{(2-9)(2+7)}{(2^+)^2-4}=\dfrac{-7\cdot9}{4^+-4}=\dfrac{-63}{0^+}=-63\cdot\infty=-\infty\\$

So, the vertical asymptotes are $x=\pm 2$

5 0

4 years ago

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