Answer: A or B im unsure but its one of them
Step-by-step explanation: dont got one sry
Well $25 is the standard price initially.
$10 is added every hour as a constant rate.
Therefore a. 25 + 10h is the right expression
Answer:
The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²
Step-by-step explanation:
Figure is attached with required naming.
Length of the Rectangle 1 = 40 m
width of the Rectangle 2 = 2000 cm = 20 m
radius of semi circle 2 =
radius of semi circle 3 =
length of the rectangle 4 = 25 m
width of the rectangle 4 = 800 cm = 8 m
length of the rectangle 5 = 10 m
width of the rectangle 5 = 800 cm = 8 m
Total Perimeter of the pitch and seating area
= length of rectangle 1 + circumference of semi circle 2 + circumference of semi circle 3 + length of rectangle 4 + 2 × width of rectangle 4 + length of rectangle 5 + 2 × width of the rectangle 5 + (length of rectangle 1 - length of rectangle 4 - length of he rectangle 5)
= 40 + π(10) + π(10) + 25 + 2 × 8 + 10 + 2 × 8 + ( 45 - 25 -10 )
= 40 + π(10) + π(10) + 25 + 16 + 10 + 16 + 10
= 117 + 20π
= 179.83 m (approx.)
Total area of the pitch and seating area
= Area of the Rectangle 1 + Area of semi circle 2 + area of semi circle 3 + area of rectangle 4 + area of rectangle 5
= 40 × 20 + π(10)² + 25 × 8 + 10 × 8
= 800 + 100π + 200 + 80
= 1080 + 314
= 1394 m²
Therefore, The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²
Answer:
The approximated value of the standard deviation is 0.35.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.
Then, the mean of the distribution of sample means is given by,
And the standard deviation of the distribution of sample means is given by,
The information provided is:
<em>n</em> = 100
<em>σ</em> = 3.5
<em>μ</em> = 66
As the sample size is quite large, i.e. <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the Normal distribution.
Then the approximated value of the standard deviation of sampling distribution of sample mean is:
Thus, the approximated value of the standard deviation is 0.35.
Answer:
Bottom Right. The net for this rectangular prism is Bottom Right.
