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Nikitich [7]
3 years ago
15

a triangle has coordinates a(-1,-2) b(-4,-2) and c(-4,-5) what are the coordinates of a' the image of point a under a dilation w

ith a scale factor of 3?
Mathematics
1 answer:
quester [9]3 years ago
8 0

9514 1404 393

Answer:

  (-3, -6)

Step-by-step explanation:

The scale factor multiplies each coordinate.

  A' = 3A = 3(-1, -2) = (-3, -6)

The image of A is ...

  A'(-3, -6)

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Answer: Chowder

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It’s 3,11

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How many parts can all 6 cutting machines cut in 1 minute?
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is there an image where i can see?

Step-by-step explanation:

4 0
3 years ago
Need help with the question in the picture learned awhile ago and forget!
xxTIMURxx [149]

Answer:

-i

Step-by-step explanation:

i^15

Divide the exponent by 4

15/4 = 3 r 3

Take the remainder and use as the exponent

i^3

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7 0
3 years ago
On Monday, you were able to spell two of your spelling words correctly. On Tuesday, you were able to spell four of your spelling
Advocard [28]

Answer: 2^5

Step-by-step explanation:

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2*2 - Monday

4*2 - Tuesday

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7 0
3 years ago
Read 2 more answers
HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            0 = ln (x - 4)

            e^{0} = e^{ln (x - 4)}

             1 = x - 4

          <u> +4 </u>  <u>    +4 </u>

             5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            1 = ln (x - 4)

            e^{1} = e^{ln (x - 4)}

             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

         e + 4 = x

          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

               x       > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0.  the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

      = - 3⁰⁺⁵

      = - 3⁵

      = -243

Horizontal Asymptote: y = 0  <em>(explanation above)</em>

5 0
3 years ago
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