Answer:
Exponential transformation.
Step-by-step explanation:
y = log_3 (x + 3) - 2
To transform this into exponential, we have:
Adding 2 to both sides
y + 2 = log_3 (x + 3)
3^(y + 2) = x + 3
x = 3^(y + 2) - 3
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
97+x=27+64
x=27+64-97
x=-6
(Hopefully this is correct)
Your answer is 5, you use the formula for a pyramid
