3x=4+13x=5x=5/32x=2* 5/32x=10/3
Answer:
13
Step-by-step explanation:
We know that a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse
5^2 + 12^2 = c^2
25+144 = c^2
169 = c^2
Taking the square root of each side
sqrt(169) = sqrt(c^2)
13 =c
Answer:
A) r=2t
B) 4
t²
C) 4(30)² which will end up being 11310 in²
Step-by-step explanation:
A) If it increases 2 inches every minute, you would take that and put it with the t, aka time.
B) A=r² which will translate into A=(2)²
C) You take the half-hour, which is 30 minutes, and translate that into t then place that into your calculator and get an answer of 11,309.73 and then round up to the whole number
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
