I genuinely don't understand . please help me asap

Please help me with this question I will give brainliest.

Ainat [17]

Answer:

All you need to remember is the rules

Step-by-step explanation:

Let us remember

a to the m power x a to the nth power is = a to the m+n power. (add the exponents)

And

a to the m power ÷ a to the nth power is = a to the m-n power. (subtract the exponents) So

14 to the -4 power x 14 to the 7 power= 14 to the -4+7 which is equal to 14 to the 3rd power

6 0

3 years ago

Plzzzz help meeeeeee

Amanda [17]

Answer:

34 jerseys

8 Social Media ads

$2,400 Spent on Radio ads

$360 per TV ad

Step-by-step explanation:

2856/84 = 34 jerseys

2000/250 = 8

200*12 = 2400

1800/5 = 360

If you know how many you have and how much they cost multiply

If you know how much was spent and how much they cost divide

If you know how much was spent and how many you have divide

8 0

3 years ago

Food costs are expected to rise 6% each month for the next year. Which series correctly depicts the cost (to the nearest cent) f

alexira [117]

For this case we have the following equation:
y = 150 * (1.06) ^ t
For the first month we have:
y = 150 * (1.06) ^ 1
y = 159 $
For the second month we have:
y = 150 * (1.06) ^ 2
y = 168.54 $
For the third month we have:
y = 150 * (1.06) ^ 1
y = 178.65 $
Answer:
d. $ 159.00 + $ 168.54 + $ 178.65

4 0

3 years ago

Read 2 more answers

Xavier said the product of a monomial and a binomial will always be a trinomial. Explain the error in his reasoning.

sergejj [24]

All that is needed is a single counter-example.

One counter-example is to multiply the monomial x^3 with the binomial x^7-10x^4

We then get...

x^3*(x^7-10x^4) = x^3*x^7 + x^3*(-10x^4)

x^3*(x^7-10x^4) = x^10 - x^7

The result we get is a binomial as there are still only two terms here. We would need three terms to have a trinomial.

5 0

3 years ago

Read 2 more answers

Women athletes at the a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample

lana [24]

Answer:

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

Step-by-step explanation:

Data given and notation

n=38 represent the random sample taken

X=22 represent the number of women athletes graduated

$\hat p=\frac{22}{38}=0.579$ estimated proportion of women athletes graduated

$p_o=0.67$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is lower than 0.67 or no:

Null hypothesis: $p \geq 0.67$

Alternative hypothesis: $p < 0.67$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

3 0

2 years ago