2 years ago

PLEASE HELP!!!!! Find AB and M

Mathematics

1 answer:

DENIUS [597]2 years ago

7 0

Answer:

Step-by-step explanation:

triangle ABC is an equilateral so all angles and sides are equal to each other

AB = 6

triangle DEF is an isosceles so two of its angles are equal to each other

a triangles angles add up to 180°

to find the measure of these angles we’ll write this equation:

x + x + 40 = 180

and solve for x

2x + 40 = 180

2x = 140

x = 70°

so mF is 70°

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AB has coordinates A(-5,9) and B(7,- 7). Points P, Q, and I are collinear

VMariaS [17]

Answer:

$\overline{QT}$

Step-by-step explanation:

We want to find the coordinates of a certain point C(x,y) such that C divides $A(x_1,y_1)$ and $B(x_2,y_2)$ in the ratio m:n=3:2

The x-coordinate is given by:

$x=\frac{mx_2+nx_1}{m+n}$

The y-coordinate is given by:

$y=\frac{my_2+ny_1}{m+n}$

AB has coordinates A(-5,9) and B(7,- 7)

We substitute the values to get:

$x=\frac{3*7+2*-5}{3+2}$

$x=\frac{21-10}{5}$

$x=\frac{11}{5}$

and

$y=\frac{3*-7+2*9}{3+2}$

$y=\frac{-21+18}{5}$

$y=-\frac{3}{5}$

Therefore C has coordinates $(\frac{11}{5},-\frac{3}{5})$

The line segment that contains C is $\overline{QT}$

See attachment.

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2 years ago