Which point is located on the line represented by the equation y+4=-5(x-3)

1 answer:

3 0

The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
y-(-4)=-5(x-3)
the point is (3,-4)

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leva [86]

-3x+9y =18

add 3x to each side

9y = 3x+18

divide by 9

y = 3/9 x +18/9

y = 1/3 x+2

the slope is 1/3

the y intercept is 2

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let y=0 to find the x intercept

-3x=18

divide by -3

x=-6

the x intercept is -6

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