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gulaghasi [49]
3 years ago
11

Which point is located on the line represented by the equation y+4=-5(x-3)

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0
The equation of a line that passes through (x1,y1) and has a slope of m is 
y-y1=m(x-x1)
given
y-(-4)=-5(x-3)
the point is (3,-4)
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The point P(8, −3) lies on the curve y = 3/(7 − x). (a) If Q is the point (x, 3/(7 − x)), use your calculator to find the slope
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Answer:

Slope of the line PQ is -63.434948.

Step-by-step explanation:

Given that,

The point P(8,-3) lies on the curve y=\frac{3}{7-x}.

If Q is the point lies on (x,\frac{3}{7-x} ).

To find:- Find the slope of line PQ.

So,  

The coordinates of point Q when it lies on (x,\frac{3}{7-x} )

        if x=1 then y= \frac{3}{7-1} =\frac{3}{6} =\frac{1}{2}

       So,   Q ≡ (1,\frac{1}{2} ) and many points can be calculated by given Equation.

Using the formula when two points (x_{1} ,y_{1} ) \& (x_{2}, y_{2}  ).

                Slope=Tan\theta = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

Then, substituting the coordinates we get,

             Slope = \frac{1-8}{\frac{1}{2}-(-3) }

             Slope = \frac{-7}{\frac{1}{2}+3 } = \frac{-7}{\frac{7}{2} }

             Slope = \frac{-14}{7}=-2

              tan\theta=-2   ⇒  \theta = tan^{-1} (-2)

               \theta= -63.434948

Therefore,

Slope of the line mPQ is -63.434948.

                     

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