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3 years ago

Which point is located on the line represented by the equation y+4=-5(x-3)

1 answer:

3 0

The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
y-(-4)=-5(x-3)
the point is (3,-4)

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7m or 7.7 m which is more precise?

Karolina [17]

7.7 meters is more precise.

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4 years ago

The point P(8, −3) lies on the curve y = 3/(7 − x). (a) If Q is the point (x, 3/(7 − x)), use your calculator to find the slope

yan [13]

Answer:

Slope of the line $PQ is -63.434948.$

Step-by-step explanation:

Given that,

The point $P(8,-3)$ lies on the curve $y=\frac{3}{7-x}$ .

If $Q$ is the point lies on $(x,\frac{3}{7-x} )$ .

To find:- Find the slope of line $PQ$ .

So,

The coordinates of point $Q$ when it lies on $(x,\frac{3}{7-x} )$

if $x=1$ then $y= \frac{3}{7-1} =\frac{3}{6} =\frac{1}{2}$

So, $Q$ ≡ $(1,\frac{1}{2} )$ and many points can be calculated by given Equation.

Using the formula when two points $(x_{1} ,y_{1} ) \& (x_{2}, y_{2} )$ .

$Slope=Tan\theta = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Then, substituting the coordinates we get,

$Slope = \frac{1-8}{\frac{1}{2}-(-3) }$

$Slope = \frac{-7}{\frac{1}{2}+3 } = \frac{-7}{\frac{7}{2} }$

$Slope = \frac{-14}{7}=-2$

$tan\theta=-2$ ⇒ $\theta = tan^{-1} (-2)$

$\theta= -63.434948$

Therefore,

Slope of the line $mPQ is -63.434948.$

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3 years ago

Solve the system of linear equations. Use linear combination aka elimination method.

Margaret [11]

2x+-3y=22 I think. I learned this last year but I don't know

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4 years ago

Which equation is equivalent to 4s= t+2

N76 [4]

Answer:

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Step-by-step explanation:

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4 years ago

The height and weight of several adults were recorded:

Natalija [7]

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3 years ago