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fenix001 [56]
3 years ago
11

Pls solve it and show your work :c

Mathematics
1 answer:
Art [367]3 years ago
6 0

Answer:

ok ill help

Step-by-step explanation:

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Motion and rate of change derivatives. Attached is the question and where I am stuck, I would really appreciate the help :)
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Answer:

A. 3 < t < 9

Step-by-step explanation:

When the particle is moving to the right, the velocity is positive.

To find the velocity, take the derivative of s(t) with respect to t.

s(t) = -t³/3 + 13t²/2 − 30t

s'(t) = -t² + 13t − 30

Find when the velocity is 0.

0 = -t² + 13t − 30

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0 = (t − 3) (t − 10)

t = 3, 10

Check the sign of s'(t) in each interval.

0 < t < 3, s'(t) < 0

3 < t < 9, s'(t) > 0

The particle moves to the right when 3 < t < 9.

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Step-by-step explanation:

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