Answer:
Step-by-step explanation:
Let the larger integer = 2x + 1
Let the second integer = 2x - 1
1/2 (2x + 1 + 2x - 1) = - 12 Combine the left
1/2(4x) = - 12 Combine 1/2 (4x)
2x = - 12 Divide by 2
2x/2 = - 12/2
x = - 6
2x + 1 = 2*-6 + 1 = -11
2x - 1 = 2*-6 - 1 = - 13
Check
-11 + - 13 = - 24
1/2(-24) = -12 which checks.
You cant say anything about an, if bn>an>0 then we could deduce that an converges.
First set up the ratio 2/5 = 10/x where <em>x</em> is the number of girls.
Now, we can use cross-products to find the missing value.
So we have (2)(x) = (5)(10).
Simplifying, we have 2x = 50.
Dividing both sides by 2, we find that x = 25.
So there are 25 girls in the class if there are 10 boys.
I’m pretty sure it’s false
So for every two girls, there's four boys. There are twice as many boys than girls, so the number of girls • 2 = your answer.
51 • 2 = 102