Answer:
Height = 5
Minimum number of vertices in a binary tree
whose height is h.
So, there must be At least one node at each of first h levels.
Minimum number of vertices = h
So, Minimum number of vertices of height 5 is 5
The maximum number of nodes in a binary tree of height h =
Substitute h = 5
The maximum number of nodes in a binary tree of height 5 =
The maximum number of nodes in a binary tree of height 5 = 63
So, the maximum number of vertices in a binary tree with height 5 is 63
Answer: the answer is c .
Step-by-step explanation: perpendicular lines should form a right angle which is 90 degrees . Choice a are intersecting llines .
Choice b is a line . Choice d are parallel lines so it is choice c .
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Answer:
14
Step-by-step explanation:
21-3^2+2
3 to the second power is 9
then, 21 - 9 + 2
left to right.....
21 - 9 = 12
12+2=14
The answer is 9m v=x^3=729
x^3=9^3
x=9m
Answer: 1.5
Step-by-step explanation: Given:
A=1/10×5 + 11²
B= 5 - 11²
If c = A + B
c = ( 1/10×5 +11²) + ( 5 - 11² )
= ( 5/10 + 121) + ( 5 - 121)
= ( 121.5) + ( -120)
= 121.5 - 120
= 1.5