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kobusy [5.1K]
3 years ago
8

In a cookie jar, 1 5 of the cookies are chocolate chip and 3 4 of the rest are peanut butter. What fraction of all the cookies i

s peanut butter?
Mathematics
2 answers:
AlekseyPX3 years ago
8 0

Answer:

3/5

Step-by-step explanation:

3/5 of 1/4 is 3/5

or 3/5*1/4= 3/5

Gala2k [10]3 years ago
4 0
The fraction is 15/20 and the fraction of chocolate cookies is 4/20
1/5 + 3/4 = 19/20
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2,10,18,26 find the 61st term
saw5 [17]

Answer:

482

Step-by-step explanation:

We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:

a_{n} =a_{1} +(n-1)d

Where a_{1} is the first term, a_{n} is the nth term, and d is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do 10-2, which is 8 , or the common difference. Since we have everything we need, it can be plugged into the equation:

a_{61} =2 + (61 - 1)*8\\a_{61} = 2 + 60*8\\a_{61} = 2 + 480\\a_{61} = 482

So, the 61st term is 482.

4 0
3 years ago
Brittany has 50 beads. 70% of the beads are gold. How many beads does Brittany have?
Ket [755]

Answer: 35 gold beads and 15 non-gold beads

Step-by-step explanation:

70% of 50

.70×50 = 35

50 - 35 = 15

6 0
4 years ago
Leroy's racing number is the difference between 11,023 and 10,090.what is it?
Mashcka [7]

Answer: 933

Step-by-step explanation: 11,023-10,090=933

8 0
3 years ago
Use long division to find the quotient. Write your answer as a decimal 99 divided by 12
ad-work [718]

Answer:

Please refer to the image

Step-by-step explanation:

7 0
3 years ago
All information is given in photo please help
zhuklara [117]
Starting on the top row
1- 84,800
5- 104,000
10- 128,000
15 - 152,000
20- 176,000

Second row
1- 84,000
5- 102,103
10-130,312
15- 166,314
20- 212,264
4 0
2 years ago
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