Answer:
23/7
Step-by-step explanation:
-7x+6=-17
-7x=-17-6
-7x=-23
7x=23
x=23/7
Answer:
18q^2 - 52q + 32
Step-by-step explanation:
We can use the Distributive Property to solve this.
(2q-4)(9q-8)
2q(9q) + 2q(-8) + -4(9q) + -4(-8)
18q^2 - 16q - 36q + 32
18q^2 - 52q + 32
18q^2 - 52q + 32
X- 6/4=7
x-6=7×4
x-6=28
x=28-6
x=22
We can't eliminate as is so we have to change something up there in the equations to get either the x values the same number but opposite signs, or the y values the same number but opposite signs. I chose to change the y values to the same number but different signs. In the first equation y is -3y and in the second one, y is -8y. The LCM of both of those numbers is 24, so we will multiply the first equation by an 8 (8*3=24) and the second equation by 3 (3*8=24) but since they are both negative right now, one of those multiplications has to involve a negative because - * - = +. Set it up like this:
8(-10x - 3y = -18)
-3(-7x - 8y = 11)
Multiply both of those all the way through to get new equations:
-80x - 24y = -144
21x +24y = -33
Now the y's cancel each other out leaving only the x's:
-59x = -177 and x = 3. Now plug that 3 into either one of the original equations to find the y value. Either equation will work; you'll get the same answer using either one. Promise. -7(3) - 8y = 11 gives a y value of -4. so your solution is (3, -4) or B above.
The value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81
<h3>How to expand the expression?</h3>
The expression is given as:
(2x -3)^4
Using the binomial expansion, we have:
Evaluate the combination factors.
So, we have:
Evaluate the exponents and the products
Hence, the value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81
Read more about binomial expansions at:
brainly.com/question/13602562
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