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2 years ago

I need the answer please help me

Mathematics

2 answers:

Flura [38]2 years ago

6 0

Answer:

I think its this but not sure

Anna71 [15]2 years ago

4 0

Answer:

-29.988 or if you round up -30

Step-by-step explanation:

1) Convert fractions to decimals

3.6 x (-8.33) = -29.988

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BRAINLIESTT ASAP! PLEASE HELP ME :)

vfiekz [6]

Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

8 0

2 years ago

Kathy needs money for a trip to Europe if she has US$300 in the bank but wants to withdraw half of it In British pounds and half

Aleks [24]

Answer: She has 21.63 more euros than pounds and has 1.23 times more euros than pounds.

Step-by-step explanation:

She has US$300, and she will withdraw half of it on pounds, and half of it in euros.

(half of US$300 is US$150)

We know that:

1 pound = US$1.6

(1 pound/US$1.6) = 1

Then US$150 = US$150*(1 pound/US$1.6) = (150/1.6) pounds = 93.75 pounds.

And we also know that:

1 euro = US$ 1.3

then:

(1 euro/US$ 1.3) = 1

This means that:

US$150 = US$150*(1 euro/US$ 1.3) = (150/1.3) euros = 115.38 euros.

This means that:

115.38 - 93.75 = 21.63

This means that she has 21.63 more euros than pounds.

and:

115.38/93.75 = 1.23

She has 1.23 times more euros than pounds.

6 0

2 years ago

Perform the indicated operation. 6/8 - 3/8

Maru [420]

Answer:

3/8

Step-by-step explanation:

(3/8) Since they have the same denominator, you can subtract the second numerator from the first so 6 minus 3 is 3. So 3/8

3 0

3 years ago

An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second

AleksAgata [21]

Answer:

The probability that the second ball is red is 71%

Step-by-step explanation:

Probabilities

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

$\displaystyle P(R)=\frac{5}{7}$

The probability is's green is computed by

$\displaystyle P(G)=\frac{2}{7}$

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

$\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}$

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

$\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}$

The total probability of the second ball being red is

$\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71$

The probability that the second ball is red is 71%

7 0

3 years ago

Whαt ís thє vαluє σf х ? <img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%20-%20%20%5C%3A%2025%20%3D%20144" i

Zigmanuir [339]

Answer:

hey mate!!

Step-by-step explanation:

−25=144

X^2=144+25

x^2=169

x=√169

x=13

Sorry mate check out the answer !

7 0

3 years ago

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