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jeyben [28]
4 years ago
5

Plz help I'm having trouble

Mathematics
2 answers:
Makovka662 [10]4 years ago
8 0
I know this isn’t an answer but if you put a picture of the notes I can do this
vodomira [7]4 years ago
5 0
1. is just identity property
2. is commutative additive
3. is associative multiplicative
4. is multiplication by zero property
5. is associative multiplicative
6. is addition by zero property
You might be interested in
Condense the following logarithm: <br><img src="https://tex.z-dn.net/?f=5%20log_%7B4%7D%28a%29%20%20-%206%20log_%7B4%7D%28b%29%2
aleksley [76]

log 4 ( a^5 ) - log 4 ( b^6 ) =

log 4 ( a^5 / b^6 )

4 0
3 years ago
15 + (5-x)/x=30 solve for x
elixir [45]

Answer:

5/16

Step-by-step explanation:

15+(5-x)/x=30

1) Subtract 15 from both sides:

(5-x)/x=15

2) Multiply both sides by x:

5-x=15x

3) Add x to both sides:

16x=5

4) Divide both sides by 16:

x=5/16

8 0
3 years ago
Enter an equation for the statement.
Advocard [28]

Answer:

40- 40

Step-by-step explanation:

hope this helps.

7 0
3 years ago
Is -6.743743… a rational or irrational number?
yaroslaw [1]

It's rational because it contains a repeating digit pattern, 743 (first option).

In particular, if

<em>x</em> = -6.743743…,

then

1000<em>x</em> = -6,743.743743… .

Subtracting, we can eliminate the trailing end and solve for <em>x</em> exactly:

1000<em>x</em> - <em>x</em> = -6,743.743743… - (-6.743743…)

999<em>x</em> = -6,737

<em>x</em> = -6,737/999

8 0
3 years ago
PLEASE HELP
alina1380 [7]

When the dice is rolled 14 times then from the given data the probability of 1,2,3,4,5,6 is 3/14,1/14,4/14,1/14,3/14,2,14.

Given Roll of dice and outcomes from 1 to 14 is 1,3,5,4,5,3,3,1,3,5,6,1,6,2.

From the given collected data we can find out number of times each number came when the dice is rolled.

Number of times 1 came=3

Number of times 2 came=1

Number of times 3 came=4

Number of times 4 came=1

Number of times 5 came=3

Number of times 6 came=2

The probabilities are in fraction form:

P(1)=3/14

P(2)=1/14

P(3)=4/14

P(4)=1/14

P(5)=3/14

P(6)=2/14

The probabilities in decimal form:

P(1)=0.21

P(2)=0.07

P(3)=0.28

P(4)=0.07

P(5)=0.21

P(6)=0.14

The probabilities in percentage:

P(1)=21%

P(2)=7%

P(3)=28%

P(4)=7%

P(5)=21%

P(6)=14%

Hence the probabilities are 3/14,1/14,4/14,1/14,3/14,2,14.

Learn more about probabilities here brainly.com/question/24756209

#SPJ10

5 0
2 years ago
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